The 1994 Murphy Cup playoffs of Roller Hockey International began in September, 1994, after the 1994 regular season. The sixteen teams that qualified, four from each division (the winner of each of the four divisions plus the three teams with the highest point totals from the teams remaining in each division), play a best-of-three series, with the third game a one 12–minute period, for the division semifinals, finals, and conference finals, and then the conference champions will play a best-of-three series, with the third game a one 12–minute period, for the Murphy Cup. All eight teams to qualify in the Eastern Conference were expansion teams, while all but two teams in the Western Conference were original teams.
In the first two rounds, the highest seed in each division is matched against the lowest remaining seed, with the two division finals winners in each conference matched against each other in the conference finals. The higher-seeded team is awarded home floor advantage, which gives them a possible maximum of two games on their home floor, with the lower-seeded team getting one. In the Murphy Cup Finals, home floor is determined based on regular season points. Thus, the Buffalo Stampede had home floor advantage in the Murphy Cup Finals. Each best-of-three series, with the third game a one 12–minute period, followed a 1–2 format. This means that the lower-seeded team had home floor for game 1, while the higher-seeded team had home floor for game 2, and if necessary, the 12–minute game 3.